本文实例讲述了Python单链表的简单实现方法，分享给大家供大家参考。具体方法如下：

通常来说，要定义一个单链表,首先定义链表元素:Element.它包含3个字段:

list:标识自己属于哪一个list

datum:改元素的value

next:下一个节点的位置

具体实现代码如下：

?123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107 class LinkedList(object): class Element(object): def __init__(self,list,datum,next): self._list = list self._datum = datum self._next = next def getDatum(self): return self._datum datum = property( fget = lambda self: self.getDatum()) def getNext(self): return self._next next = property( fget = lambda self: self.getNext()) def __init__(self): self._head = None self._tail = None def getHead(self): return self._head head = property( fget = lambda self: self.getHead()) def prepend(self,item): tmp = self.Element (self,item,self._head) if self._head is None: self._tail = tmp self._head = tmp def insert(self, pos, item): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > pos-1: return -1 tmp = self.Element(self, item, p._next) p._next = tmp return 1 def getItem(self, pos): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > post-1: return -1 return p._datum def delete(self, pos): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > post-1: return -1 q = p._next p._nex = q._next datum = p._datum return datum def setItem(self, pos, item): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 if p == None or i > post-1: return -1 p._datum = item return 1 def find(self, pos, item): i = 0 p = self._head while p != None and i < pos -1: if p._datum == item: return 1 p = p._next i += 1 return -1 def empty(self): if self._head == None: return 1 return 0 def size(self): i = 0 p = self._head while p != None and i < pos -1: p = p._next i += 1 return i def clear(self): self._head = None self._tail = None test = LinkedList() test.prepend('test0') print test.insert(1, 'test') print test.head.datum print test.head.next.datum

希望本文所述对大家的Python程序设计有所帮助。

更多信息请查看IT技术专栏